Quick Quiz: Population Control and Sex Ratios

Sorry for the light blogging this week. Finals are this week and next, and so I'm pretty swamped. Today I'm going to pose a straightforward but slightly counterintuitive probability question, of the sort that in modified forms aren't so uncommon in physics:

A densely populated authoritarian state issues the following population control policy: each family may have one child with no restrictions. If that child is male, the family is not allowed to have more children. If that child is female, the family may have one more child. The family may not have a another child regardless of the sex of the second child. What will the final equilibrium ratio of boys to girls after this policy is put in place? Assume full compliance and no "cheating" (as in sex-selective abortion or infanticide). Show your work.

A lot of very smart people get this wrong. But a lot of them get it right too. Which will you be?

More like this

If we assume that 50% of births are male, and that no parents have, for some reason, a bias toward having babies of one or the other sex, then this is too easy. Let's add more rules: you can have a third baby, but only if there are at least five left-handed grandmothers living with 72 metres of your home. If your first baby is born on a Tuesday or at night, you can have a second child, but it must be named "Fizzbin" if a boy, "Fizzbina" if a girl.

In the end, we're asking "if 50% of all pregnancies result in a male baby, then what fraction of babies are male?" Still 50%. It doesn't matter how you hand out the pregnancy licenses.

The first round will be 0.5 M and 0.5 F, 1:1. The second round will be 0.25 M and 0.25 F. Looks like the sum stays 1:1. 50% of families with 1 M, 25% with 1 M 1F, 25% with 2 F.

If the correct answer is 50%, and it seems to me almost obvious that it is, what is counter-intuitive about it?

This (50% conclusion) makes some assumptions that I am not sure about:

Does the probability of a male or female child remain constant independent of population density? I seem to recall reading something about this years ago, but can't quickly find anything.

Are all couples equally likely to produce male and female children. In other words, are the genders of the children in two child families independent?

That's cute, you should still have a 1:1 sex ratio.

The one wrinkle I can think of is if some couples are biased to having males while others are biased to females. Then drawing random births you still get 50/50 M:F ratio, but imposing the rule changes things. It becomes a bit more Baysian, and many of the couples who have a girl first could be expected to have a second girl. Then the sex ratio of births will be biased to female.

It does seem pretty clearly fifty percent, for the reasons outlines above. Maybe it's not though- since you promised that a lot of smart people get this wrong, and this seems too obvious. I'm going to have to think it over- this is not my final answer!

The "final" equilibrium ratio is undefined because 0/0 is undefined. Each new generation is only 0.75 times the size of the previous one. But while you're getting there the M/F ratio remains close to 1/1.

Each pregnancy is a distinct event with no influence on the outcome of any other pregnancy. So, neglecting twins and higher N-tuples (as well as selective abortion), the sex distribution will be the same whether or not these rules are imposed.

Proof: Let P be the probability that the pregnancy results in a male child. Thus P is the fraction of couples who have one child who is male. The remaining couples then have a second child, giving P(1-P) as the fraction who have one boy and one girl, and (1-P)^2 as the fraction with two girls. We therefore have P + P(1-P) boys and 2*(1-P)^2 + P(1-P) girls. Expanding the expressions, the ratio of boys to girls is (2P-P^2)/(2-3P+P^2). Both numerator and denominator contain a factor 2-P, which we cancel to arrive at P/(1-P), which is exactly the ratio we would get if there were no restrictions.

By Eric Lund (not verified) on 06 May 2009 #permalink

Are we to assume that everyone who has a female baby in the first round will have a second child? The higher the percentage of parents choosing to stick with just one girl, the lower the percentage of girls in the overall population.

Does the question assume that all couples will have children until their permission runs out? We know that couples who choose zero offspring do not affect the answer. But what about couples who choose to stop after one girl? Is the problem completely specified?

Ok, the size of each new generation is less than 75% of the size of the previous generation. I think it's proper to re-state the rules: no woman will be permitted to have more than two children and the average number per woman will be less than 1.5. That, it seems, makes it certain that the population will vanish.

@ aaron:

Nope, its still 50/50. Say you have 100 families, the first children will (approximately) 50 boys and 50 girls. Of the 50 families that can have another child, say 40 do. This will result in 20 more boys, and 20 more girls, for a total of 70 boys and 70 girls, a 50/50 split.

Are we to assume that everyone who has a female baby in the first round will have a second child? The higher the percentage of parents choosing to stick with just one girl, the lower the percentage of girls in the overall population.

If the probability of any second pregnancy producing a boy is 50%, it doesn't make any difference. 50% of first pregnancies produce a boy and 50% of second pregnancies produce a boy.

Well, there is a fourth outcome possible - one girl. Of course, plugging that in leaves the ratio at 1:1, unless I screwed something up.

Showing my work:
First child is either male or female, with probability 0.5 for each.
A boy means no more children, so this outcome is 1M with probability 0.5.
A girl means the parents choose whether or not to have another child.
Choosing to stop at one occurs with probability x, so the outcome 1F occurs 0.5*x of the time.
Choosing to continue occurs with probability 1 - x, so the outcomes 1M + 1F and 2F each occur 0.5*0.5*(1-x) of the time.
So the expected outcome is 0.5*M+0.5*x*F+(0.5*(1-x))*(1.5*F+0.5*M) or (0.75-0.25*x)*(F+M) in a family; because F and M have the same coefficient, it follows that the expected ratio of M:F is 1:1.

By Mark Cook (not verified) on 06 May 2009 #permalink

I "cheated" and ran a simulation, where each woman has the maximum number of children. The end result is of course that they become extinct, while in the mean time, the sex ratio stays 50/50 (or corrects to this value in one generation if the starting ratio differs).

2/5 M 3/5 F

There's three possible outcomes M, MF or FF each occurring with an equal probability (full compliance). The next generation will simply be MMFFF which gives the fractions above.

Actually it's not true that they occur with equal probability. I can't remember what my justification was for thinking that.

Obviously, there are a number of "real world" things that can mess this up a bit:

1) The ratio of boys:girls isn't 50:50 in the real world. This, however, doesn't matter to the logic problem - the actual answer is "whatever the ratio of boys:girls was before the program began, assuming no human evolution."

2) This assumes no human evolution. :) Since families that have a son first get to have a second child, it seems reasonable to think that the easiest way to have a second child would be to always have boys. Thus, mutations that result in 100% boys would have a really strong tendency to spread through the population. What the final equilibrium is in that case is awfully hard to determine (especially if you allow further mutations of "have a boy first, then girls"). Also, what happens if you have sextuplets in your first pregnancy? Do you have to have an abortion, or kill the subsequent 5? These, too, could have significant selection pressures...

And, yeah, I know this is a physics blog, so we're not allowed to worry about that messy biology stuff...

If the probability of a girl is .62 and if we allow men to be members of more than one family each and if each female born has the maximum number of children in accordance with the rules, then we can have a stable population.

I'm convinced. I guess that makes me one of the smart people who got it wrong.

As usual my readers impress me! The ratio remains 50:50 in the absence of complications. Smart people who aren't used to thinking about independent events often tend to assume that because the system is built to make sure that more families have a boy than don't, the system will thus generate more boys. But each pregnancy is a coin flip, and you'll end up with a 50:50 split no matter what scheme you use to decide who flips what.

I didn't specify the percentage of families who would be satisfied with one girl, but as a few commenters noted it won't make a difference to the ratio.

Of course let the system run long enough and the the ratio will become undefined by virtue of the extinction of the population, since on average each set of parents will produce fewer than the 2 children needed to replace them.

Exctinction? Maybe not. To make the simplest assumptions, couples which have a female first child have twice as many children as couples who have a male child first. Huge difference in fitness, so there will be selection for couples who have a female child first. In the first generation, all the female children and 1/3 the male children originate from couples who have a female child first. So the population should evolve in the direction of having more and more first birth females. Maybe the population reaches 100% female first births and stabilizes. Yes, probably goes extinct.

There was an article in Nature, back in the 90's, about the slight skew to more male births. Turns out this is true of populatins where male children are more valued than female children. In the few populations where females are valued more highly than males, the skew is the other way.

By Jim Thomeson (not verified) on 06 May 2009 #permalink

OK so the answer is 1:1 or 50:50. I am not 100% sure yet that I get it. I will think about it but in the meantime:
What is wrong with the following logic?

It looks like there are three possibilities:
i.e if there are an infinite amount of families then each can only experience one the following states:

1. 1 male -> 0 females
2. 1 female-> 1 male
3. 1 female -> 1 female

There are now 2 males for 3 females.
Each family has equal chance of being either in state 1, 2 or 3. Then, if we have an infinite amount of these families, shouldn't the ratio remain 2 males to 3 females?

thanks.

Krist, half of families will have a male first and fall into your first state. The other half will have a female and fall into either the second or third state, with half of them in each. So states 2 and 3 each make up 25% of the population while state 1 makes up 50%. Adjust by multiplying the first state by 2, since twice as many families fall into it as opposed to either state 2 or 3. Now you have 3 males and 3 females.

The error that crops up in this problem is the most common probability error, that of assuming that all events have equal probability. It's the most common simplifying assumption in the basic study of probability, and we use it so much it's easy to forget that it is an assumption.

Trey- wonderful explanation! I get it now. I was thinking that each state has a 1/3 probability of occurring since there are three possibilities and each is just as likely to occur as the others. But actually state 1 is twice the other two! Makes sense now. I was thinking too globally about each family unit rather than each individual unit-the 50% chance of male and 50% female.

@Krist: what Trey described is correct. it is known as the density of states, a subject Matt has mentioned recently in the Bose-Einstein posts. (number 2 i believe)

I assumed that it was going to be a complex question, and so I drew a flow chart type diagram with the various possible outcomes of each outcomes as I read it, and when done, had to ask myself if it was a trick question because it was blindingly obvious that it was always 50/50 no matter what, but that could be because the diagram made forced me to stay within the declared parameters and not make any assumptions or intuitive leaps of logic.

By Karl Withakay (not verified) on 07 May 2009 #permalink

Please forgive my composition typo of "outcomes of each outcomes " in place of "of outcomes of each possibility".

By Karl Withakay (not verified) on 07 May 2009 #permalink

It seemed pretty obvious to me that the correct answer (assuming no complicating issues such as unequal gender probabilities) is that the population will become 50% male and 50% female. I neglected to notice that the population would become extinct. But thinking on it, it occurs to me that the reason I may have found the "correct" answer intuitive is because I am familiar with the "Monte Hall" problem. That wiki thing has an interesting discussion on the Monte Hall problem and other "paradoxes" similar to it.

I'm surprised nobody has mentioned it up to this point, but the policy Matt described is not theoretical. It's the actual population control policy in place in rural areas of China. (In urban areas the policy is even stricter: maximum one child even if it's a girl.) I assume they don't intend to leave it in place indefinitely, but for now a smaller population in China would be a good thing overall. One side effect will be that India, which has no similar policy, is expected to overtake China in population by 2050.

@hedberg: The general case isn't that hard; I solved it upthread. It doesn't matter what the expected gender ratio would be without the policy; you get the same gender ratio with the policy in place.

By Eric Lund (not verified) on 07 May 2009 #permalink

"Exctinction? Maybe not. To make the simplest assumptions, couples which have a female first child have twice as many children as couples who have a male child first. Huge difference in fitness, so there will be selection for couples who have a female child first. In the first generation, all the female children and 1/3 the male children originate from couples who have a female child first. So the population should evolve in the direction of having more and more first birth females. Maybe the population reaches 100% female first births and stabilizes. Yes, probably goes extinct."

Well you gotta consider that once there is a big majority of females in the population a male child can generate a lot more grandchildren than a female can. I suspect we would see some sort of equilibrium with a skewed sex ratio but not 100% females.

"There was an article in Nature, back in the 90's, about the slight skew to more male births. Turns out this is true of populatins where male children are more valued than female children. In the few populations where females are valued more highly than males, the skew is the other way."

Surely that is because of selective abortion or some similar feature and not some inborn feature of the human race?

Natural selection does not care about what social value the genders are ascribed. If one sex is less represented it will have more reproductive success on average causing the balance to swing back towards equality. That should suffice to make balanced gender ratios the most favorable under most circumstances. Fishers classical explanation for balanced sex ratios should work regardless of how patriarchal or matriarchal a culture is.

Johan: selection pressure can only draw from the phase space of extant entities. One cannot assume that there is some heritable trait present in the population that skews the birth rate. I suppose that an X-linked fatal recessive would do the job, a female with that trait would, for every four live births, produce 1 normal male (males cannot be carriers), two carrier females, and one normal female. They would also have reduced fertility (0.75 of normal), so this trait should be selected out over the long term in the absence of manipulations such as we are positing here.

Consider another case. In the United States there is a tradition of shooting at deer at some times of the year. This produces a strong selection pressure toward bulletproof, or at least bullet-resistant, deer. Still no clear success on that evolutionary front after many generations.

I am not sure against which of my statements you are arguing against but probably the first one. My point was mostly to dispute a previous argument about the effects of natural selection not to make any definitive predictions myself.

Obviously whether sex-skewing mutations would arise depends on the time-scales involved before the population went extinct.

Johan makes some interesting points. If there is no genetic mechanism regulating the sex of first-birthed children then differences in fitness are meaningless in this sitution. If we postulate such mechanisms, then we might predict an eventual stable population with 100% female first births, and 100% male second births. If there is no such genetic mechanism, the population will simply shrink by 25% each generation.

By Jim Thomerson (not verified) on 08 May 2009 #permalink

There is a slightly skewed natural propensity for boy babies, but boy babies have a higher mortality rate than girl babies, so it sort of balances out.

Marc: I think your analysis could work, but it depends on whether the babies are bosons or fermions.

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Awareness is assured all-round advance asset. Awareness is infinite treasure. It is the real; unseperatable ever preventive and ever protective mobile wealth. Awareness is required in every step of life. To spread such precious awareness easily and effectively to the entire mankind, Srimission, Awareness foundation for the world peace, is spreading ART OF AWARENESS LIVING in very simple ways. One among such popular methods is PERIODICAL AWARENESS LECTURES (PALs).
WHAT ARE PERIODICAL AWARENESS LECTURES?
Periodical Awareness Lectures are very attractive. In fact, in other words the programme is known as âUnique Unlimited Universityâ. Because, from an university one gets a degree certificate in one subject, in which he is qualified, whereas at Periodical Awareness Lectures, every interesting individual gets reasonable enough knowledge in the subject conducted every time, lifelong. Lectures will be conducted on all common manâs needy subjects in routine life, strictly excluding religion and political subjects.
WHO WILL DELIVER PERIODICAL AWARENESS LECTURES?
Periodical Awareness lectures are delivered by well qualified, experienced professionals, on their respective subjects in whom they have full command. Any Doctors, Lawyers, Professors, Professionals, scholars, scientists, personality/management development trainers, councilors, not one, anybody who can add value to enrich lives with their knowledge treasure can present their lectures. In addition to that, persons who want to develop their public speaking skills will be given training and encouraged to develop their skills by presenting lectures on PALs platform. Anybody, who will think that he has subject to deliver a lecture on PALs platform, can register as a resource person.
WHERE PERIODICAL AWARENESS LECTURES WILL BE CONDUCTED?
Usually PALs will be conducted at Metropolitan Cities, District headquarters/heavily populated towns. PALs will be conducted at Higher secondary Schools, PU Colleges, Tutorial Colleges, Libraries, Associations, Clubs, such any other place where interesting listeners group is available, provided they have a classroom type accommodation for audience to sit is available. Such accommodation will be utilized periodically, maximum 2 hours, once a month, on the local weekly holiday. Interesting such accommodation owners can register with Srimission for the consideration of their venue to conduct PALs.
WHO WILL CONDUCT PALs?
PALs will be conducted by Local organizer (LO).Any person who has experience in public speaking ability, to coordinate resource persons as well as, attract audience and confident that he can raise all the credentials of PALs to further highs, can register as an LO. It is an added advantage, if the LO is well versed with English, apart from local language.
WHEN PERIODICAL AWARENESS LECTURES WILL BE CONDUCTED?
PALs will be conduct minimum quarterly once, initially. Then on the improvement of audience strength, the frequency of PALs will be increased steadily to bimonthly and later to monthly. Quarterly PALs are conducted in the months of January, April, July and October. In case of Bi monthly, PALs are conducted in the six even months of the English calendar.
WHAT ARE THE TIMINGS OF THE PERIODICAL AWARENESS LECTURES?
Generally PALs are conducted on the 4th Sunday (or local 4th weekly holiday) of any calendar month, from 5-00 to 7-00 p.m at the local venue. Even though day and time of conducting PALs is left to the local PALs team, it should be bear in mind that ultimately maximum audience to attend the PALs, to make them all-round success.
Who are all voluntarily interesting to offer their valuable services as Local Organizers, Resource Persons/Speakers, Venue Providers and support Art Of Awareness Livingâs PALs program me, they are all requested to register with Srimission with their Name, postal address, mobile as well as land line phone numbers, email id etc. to email to srimission@gmail.com, or by phone to ph nos:91 80 23641839/919900004200.
For further Art of Awareness living various activities; all-round, easy simple, single window awareness solutions visit website: www.srimission.org.