
"In this paper we demonstrate that a sufficiently advanced civilization could, in principal, manipulate the radius of the extra dimension to locally adjust the value of the cosmological constant."

"A foundation started by the late Harold Alfond, founder of Dexter Shoe Co., will give new parents an opportunity to sign up for a $500 down payment for their young son or daughter's college education."

My immediate answer is "zero," because that's almost always the answer to problems with no numbers given...

Wired visits NIST in Boulder

Anyone who says otherwise is a fool.

Toner Low.
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I suspect zero is correct as well. Since parallel resisters should halve the resistance, an infinite parallel circuit will rapidly converge on zero creating, essentially, a wire.
Re: precise clocks
NIST F1 is a frequency standard, not a clock, and NIST doesn't provide the time for GPS. That comes from the US Naval Observatory.
Not an official spokesperson.
I'm no physicist, but this answer from Hit3K at xkcd forum seems to have been accepted:
Do you think my googling abilities will be enough to land me a job there?
Numbers are given. They are ideal _1_ ohm resistors.
""In this paper we demonstrate that a sufficiently advanced civilization could, in principal, manipulate the radius of the extra dimension to locally adjust the value of the cosmological constant.""
Are we supposed to take people who don't know the difference between "principle" and "principal" seriously?
Since parallel resisters should halve the resistance, an infinite parallel circuit will rapidly converge on zero creating, essentially, a wire.
That's what I thought at first too, but it turned out the resistors can't always be summed as if they were in parallel. Consider that the current has only four paths out of the starting node, and each of those links has a resistance of 1 ohm. Even if the entire rest of the network had an equivalent resistance of zero, the total resistance couldn't be less than 0.25 ohms. Essentially, much of a given path from start to finish overlaps a whole bunch of other paths, so they aren't in parallel.
For example, if you cut out two rows and the connections between them, I think the resistance between opposite nodes is 1/sqrt(3) ohms instead of zero, even though there are infinitely many paths for current to take. (After seeing the solution Eyal Ben David posted, suddenly I don't feel so badly about not getting the correct answer.)
This problem would actually be easier for an infinite dimensional lattice of resistors. Then, since there is an infinite valence at each node, there really are an infinite number of nonoverlapping paths from start to finish, and the resistance would be zero. Conversely, in an infinite onedimensional line of resistors, the resistance between adjacent resistors would be 1 ohm, I think.
Ahh, I see. Good point. Been a decade since I took electronics, sigh.
Despite the several learned commentators, the resistance is certainly not zero, as an example calculation for a different pair of points will show.
Along this line, my favorite nerd catcher was the American Mathematical Monthly problem that asked (more or less) "what is the minimum number of one ohm resistors that can be assembled to form a circuit with a total resistance of pi ohm to within one part in one million?"